This quadratic transformations worksheet covers every move a parabola can make — translation, reflection, rotation, and stretching — read off one equation, with 20 practice problems and a full answer key.
By Berke Sahbazoglu · 6,000+ hours & 200+ students tutored · 10+ years teaching Algebra I & II · BS Biochemistry (Washington University in St. Louis), MS Bioinformatics (UMGC) · Burke Tutoring in Fremont
Published July 28, 2026 · Last updated
On this page: translation · reflection · stretch & shrink · rotation · the order trap · practice problems · answer key · common questions
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A parabola only knows four tricks: it can slide, flip, spin, and change width. This quadratic transformations worksheet takes them one at a time, and all four are hiding in the same equation.
y = a(x − h)² + k
a = width and flip · h = left and right · k = up and down
Slides only.
Same shape, new address.
Flips it upside down.
Smile becomes frown.
Narrow or wide.
Vertex stays put.
Spin it half a turn.
Yes, it is a flip in disguise.
The shape never changes. Only the vertex moves — to (h, k), every time.
| Equation | Vertex | |
|---|---|---|
| y = x²the parent — nothing done to it | (0, 0) | |
| y = (x − 4)²right 4 | (4, 0) | |
| y = x² − 6down 6 | (0, −6) | |
| y = (x + 5)² + 2left 5, up 2 | (−5, 2) | |
Minus four inside the bracket moves the graph right four. Every student has argued with me about this. The bracket is (x − h), so (x − 4)² means h = +4. Outside the bracket, k behaves itself: −6 really does mean down.
Negative in front of a flips the parabola over the x-axis. Flipping over the y-axis is the transformation nobody notices, because on a parabola sitting at x = 0 it does absolutely nothing.
| Equation | Vertex | |
|---|---|---|
| y = (x − 3)² − 4the starting curve | (3, −4) | |
| y = −(x − 3)² + 4flipped over the x-axis | (3, 4) | |
| y = (x + 3)² − 4mirrored over the y-axis | (−3, −4) | |
Flipping over the x-axis negates the whole right side — the k has to change sign too. That is the step people forget. And notice the y-axis mirror only moved the vertex sideways; the parabola still opens up.
Bigger a, skinnier parabola. Smaller a, wider parabola. The vertex does not move an inch, which is the giveaway.
| Equation | At x = 1 | |
|---|---|---|
| y = x²parent | y = 1 | |
| y = 3x²stretch ×3 — narrower | y = 3 | |
| y = ¼x²shrink ×¼ — wider | y = 0.25 | |
A stretch multiplies every y-value by a, so the point one step from the vertex rises from 1 to a. The parabola looks taller because it got narrower. If you catch yourself saying the vertex went up, check again — it didn't.
Ten minutes with a slider beats ten minutes of me talking: this GeoGebra applet with a, h, and k sliders is the fastest way to feel it, and Desmos works too if you type the equations yourself.
Rotate a parabola 180° about its own vertex and you get… the exact same curve you'd get by flipping it over the x-axis. Two different instructions, one answer. Rotate it about the origin instead and the vertex takes a trip too.
| Equation | Vertex | |
|---|---|---|
| y = (x − 3)² − 2original | (3, −2) | |
| y = −(x − 3)² − 2180° about its own vertex | (3, −2) | |
| y = −(x + 3)² + 2180° about the origin | (−3, 2) | |
The rule for a half-turn about the origin is short: every point (x, y) becomes (−x, −y). Replace x with −x, replace y with −y, solve for y, done.
Turn a parabola a quarter turn and it opens sideways — x = y². Two y-values for one x, so it fails the vertical line test and stops being a function. Still a parabola, just no longer welcome in Algebra I. That is why rotation problems come in 180° servings.
Stretch first, then slide. Do it backwards and you'll stretch the shift too.
Take y = x², stretch by 2, then move up 3: you get y = 2x² + 3. Move up 3 first and then stretch: y = 2(x² + 3) = 2x² + 6. Different graph, same words in a different order. Purplemath walks through more of these in point-by-point detail, and the standard behind all of it is CCSS HSF.BF.B.3 if you need the official wording for a lesson plan.
Once you can read a, h, and k off a graph, the related skills are finding the vertex and axis of symmetry, converting between vertex form and intercept form, and completing the square to get standard form into y = a(x − h)² + k in the first place.
Part A is reading transformations off an equation. Part B asks you to build the equation. Show your work in the space provided.
Part A — describe the transformation from y = x², then give the vertex
Part B — write the equation, or read it off the graph
Part A
The 7 is outside the square, so it moves the whole graph.
Up 7 · vertex (0, 7)
Inside the bracket, and (x − h) means h = 6.
Right 6 · vertex (6, 0)
a = −1. Same width, opposite direction.
Reflected over the x-axis (same as a 180° turn about the vertex) · vertex (0, 0)
a = 5, so every y-value is five times bigger.
Vertical stretch by 5, narrower · vertex (0, 0)
(x + 2) is (x − (−2)), so h = −2. The −9 drops it.
Left 2, down 9 · vertex (−2, −9)
a is between 0 and 1.
Vertical shrink by ⅓, wider · vertex (0, 0)
Three things at once: negative a, h = 1, k = 4.
Flipped over the x-axis, right 1, up 4 · vertex (1, 4)
a = 2 and h = −3.
Stretch by 2, left 3 · vertex (−3, 0)
(−x)² = x². A y-axis reflection lands the parabola right back on itself.
No visible change · vertex (0, 0)
Negative flips it, ½ widens it, then h = 4 and k = −1 move it.
Flipped, shrink by ½, right 4, down 1 · vertex (4, −1)
Part B
Left 3 puts h = −3, so the bracket is (x + 3). Down 5 puts k = −5.
y = (x + 3)² − 5
Flip and stretch both live in a, giving a = −4. The move up comes last, so it is not multiplied by 4.
y = −4x² + 2
The vertex is the pivot, so it stays at (2, 3). Only a changes sign.
y = −(x − 2)² + 3
Every point (x, y) goes to (−x, −y), so the vertex (2, 3) lands at (−2, −3) and the curve opens down.
y = −(x + 2)² − 3
The shift right 1 sends x = 3 to x = 4. The y-value gets multiplied by −2 and then raised by 5: −2(9) + 5. Check it: −2(4 − 1)² + 5 = −18 + 5.
(4, −13)
Compare the size of a, ignoring the sign: 3 beats 0.8.
y = −3x² is narrower, and it is also the one opening downward
Two right of the vertex the curve is 4 up, and 4 = a(2)², so a = 1.
y = (x + 3)² + 1
It opens down, so a is negative. Two left of the vertex the curve drops 4: −4 = a(2)², so a = −1.
y = −(x − 2)² + 4
At x = 2 the curve has climbed 2 units: 2 = a(2)², so a = ½. Wider than the parent, which matches the picture.
y = ½x² − 2
Later means right, so h goes from 3 to 5. Higher means up, so k goes from 40 to 50. The −4 is untouched.
h = −4(t − 5)² + 50 · maximum 50 feet, now at t = 5 seconds
Every answer above was checked against the original equation or graph before publishing, most recently on July 28, 2026. Please reach out by email at burketutoringinfremont@outlook.com or text (510) 453-0350 if any mistakes are spotted.
Translation (sliding, from h and k), reflection (flipping, from a negative a), stretching or shrinking (width, from the size of a), and rotation — which for a parabola means a 180° turn.
Because vertex form is written (x − h). Matching (x − 4) to (x − h) gives h = 4, and the vertex sits at x = h. If it helps, ask what x makes the bracket zero: x = 4, which is where the vertex has to be.
About its own vertex, yes — identical curve. About any other point, no: the vertex moves as well, so you get a flipped parabola somewhere else entirely.
No. Only h and k move the vertex. Changing a squeezes or flips the curve around a vertex that stays exactly where it was.
Algebra I, usually grades 8 to 10, and again in Algebra II when function families come back around. Part A of this quadratic transformations worksheet works as a warm-up; Part B is closer to test level. For extra reps, the Function Flyer lets you drag coefficients and watch the graph react.
Transformations are the shortcut; the long way still has to work too. Try graphing quadratic functions from scratch, writing a parabola's equation from a graph, and using the discriminant to count roots. When it comes time to solve, there is factoring and the quadratic formula — and if you want to see how quadratics stack up against the other function families, try comparing linear, quadratic, and exponential functions.
Berke has taught K–12 math and science for more than 10 years, logging over 6,000 tutoring hours with 200+ students. He holds a BS in Biochemistry from Washington University in St. Louis and an MS in Bioinformatics from UMGC.
He writes every worksheet on this site from problems he actually uses in sessions. This quadratic transformations worksheet started as a one-page handout for an Algebra I student who kept shifting parabolas the wrong way — the "h lies to your face" box exists because that argument happens at least once a month.
How these are made: problems are prepared from previous class notes and assigned homework, and every answer is checked before publishing. Corrections come in by email or text and get fixed the same week.
If you want someone sitting next to you while you work through this quadratic transformations worksheet, Burke Tutoring offers in-home algebra tutoring in Fremont, Newark, and Union City. Call (510) 453-0350.
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