From an equation
The variable is in the exponent, so the function is exponential. Each step of 1 in x multiplies y by 0.8. It keeps 80% of its previous value: a 20% decrease per step.
Identify functions from equations, tables, and graphs, then use them to compare real situations. There are 18 core questions and 6 extension questions, with an answer key that explains the reasoning.
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By Berke Sahbazoglu · Revised October 14, 2026
Start with what changes when the input increases by the same amount. A graph gives a useful clue; an equation or table helps you check it.
| Family | Basic equation | Table pattern | Graph |
|---|---|---|---|
| Linear | y = mx + b | Equal first differences | A straight line |
| Quadratic | y = ax² + bx + c a ≠ 0 | Equal, nonzero second differences | A parabola with a vertex and a vertical line of symmetry |
| Exponential | y = a·bx a ≠ 0; b > 0; b ≠ 1 | Equal ratios between consecutive outputs | A curve approaching a horizontal asymptote |
Check the x-values first. Differences and ratios should be compared over equal input steps. For the basic exponential form above, the asymptote is y = 0. With a positive starting value, a base above 1 gives growth; a base between 0 and 1 gives decay.
In these questions, choose among the three stated families. A short table suggests the intended model; by itself, it does not prove what happens at every other input.
Look for a specific piece of evidence before choosing a family.
The variable is in the exponent, so the function is exponential. Each step of 1 in x multiplies y by 0.8. It keeps 80% of its previous value: a 20% decrease per step.
| x | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| y | 3 | 5 | 11 | 21 | 35 |
First differences: 2, 6, 10, 14
Second differences: 4, 4, 4
The inputs step evenly. The first differences change, but the second differences stay at 4. This is a quadratic pattern; y = 2x² + 3 fits the values.
The curve turns at (1, −2). Points equally far from x = 1 have the same height. That turning point and symmetry make it quadratic: y = (x − 1)² − 2.
Try each question before opening its answer. Name the family and explain what gave it away. For the extension questions, show your calculation and include units when needed.
The questions below match the PDFs. Print the student worksheet for writing space.
01y = 4x - 7
02y = 12 - 3x
03y = 2x² - 5x + 1
04y = -(x - 3)² + 4
05y = 5(1.4)x
06y = 16(1/2)x
07Identify the pattern and name the family.
| x | -2 | -1 | 0 | 1 | 2 |
|---|---|---|---|---|---|
| y | -1 | 2 | 5 | 8 | 11 |
08Identify the pattern and name the family.
| x | 0 | 2 | 4 | 6 | 8 |
|---|---|---|---|---|---|
| y | 12 | 8 | 4 | 0 | -4 |
09Identify the pattern and name the family.
| x | -2 | -1 | 0 | 1 | 2 |
|---|---|---|---|---|---|
| y | 9 | 3 | 1 | 3 | 9 |
10Identify the pattern and name the family.
| x | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| y | 5 | 4 | 1 | -4 | -11 |
11Identify the pattern and name the family.
| x | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| y | 3 | 6 | 12 | 24 | 48 |
12Identify the pattern and name the family.
| x | 0 | 2 | 4 | 6 | 8 |
|---|---|---|---|---|---|
| y | 256 | 64 | 16 | 4 | 1 |
13Graph G1
Name the function family. Describe the graph feature you used.
14Graph G2
Name the function family. Describe the graph feature you used.
15Graph G3
Name the function family. Describe the graph feature you used.
16Graph G4
Name the function family. Describe the graph feature you used.
17Graph G5
Name the function family. Describe the graph feature you used.
18Graph G6
Name the function family. Describe the graph feature you used.
19A culture starts with 200 bacteria and doubles every 6 hours. Assume this doubling pattern continues.
a. Write B(t), the number of bacteria after t hours, and name the function family.
b. How many bacteria does the model predict after 18 hours?
20A phone plan charges $30 per month plus $0.10 for each gigabyte of data used. For this problem, ignore taxes and other fees.
a. Write C(g), the monthly cost for g gigabytes, and name the function family.
b. What is the cost for 45 gigabytes?
21A car is worth $24,000 when purchased. A model predicts that it loses 15% of its value each year.
a. Write V(t), the predicted value after t years, and name the function family.
b. Find the predicted value after 3 years.
22Two hypothetical account models start at $500. In model A, $25 is added each month: A(n) = 500 + 25n. In model B, the balance grows by 4% each month, with no deposits: B(n) = 500(1.04)n. Here n is the number of months.
a. Name the family for each model.
b. Compare the balances after 12 months and after 24 months. Round only the final amounts to the nearest cent.
23Compare Q(x) = x² and E(x) = 2x.
a. Find both values at x = 2, 3, 4 and 5. State which is larger at each input, or say they are equal.
b. Is an exponential function always larger than a quadratic at the same input? Use your results to explain.
24Compare L(x) = 50x, Q(x) = x² and E(x) = 1.2x for positive whole-number inputs. Use a calculator or a spreadsheet for this problem.
a. Find all three values at x = 10 and at x = 100. Round exponential values to two decimal places. Order the values from least to greatest at each input.
b. Starting at x = 1, check consecutive whole-number inputs. What is the first input where E(x) is greater than both L(x) and Q(x)? Show the values at that input and the preceding input.
Open the answer when you are ready to check your work. A correct family name is only part of the answer; your evidence matters too.
Download the complete answer key for a printable copy.
The equation has the form y = mx + b. Each increase of 1 in x adds 4 to y.
Rewrite it as y = -3x + 12. The slope is -3, so the outputs decrease at a constant rate.
The highest power of x is 2, and its coefficient is 2. This is y = ax² + bx + c with a ≠ 0.
The squared expression makes it quadratic. Expanding gives y = -x² + 6x - 5; the graph opens downward.
The variable x is in the exponent. The base 1.4 is greater than 1, so each increase of 1 in x multiplies y by 1.4.
The variable x is in the exponent. The base 1/2 lies between 0 and 1, so each increase of 1 in x halves y.
The x-values increase by 1. The y-values change by +3, +3, +3, +3. A matching model is y = 3x + 5.
The x-values increase by 2. The y-values change by -4 each time, so the slope is -4/2 = -2. A matching model is y = -2x + 12.
For x-steps of 1, the first differences are -6, -2, +2, +6. Their differences are +4, +4, +4. A matching model is y = 2x² + 1.
For x-steps of 1, the first differences are -1, -3, -5, -7. Their differences are -2, -2, -2. A matching model is y = -x² + 5.
The x-values increase by 1, and each output is twice the preceding output. A matching model is y = 3(2)x.
The x-values increase by 2. The output ratios are all 1/4. The factor for an x-step of 1 is 1/2, so a matching model is y = 256(1/2)x.
G1 is a straight line. It rises at a constant rate as x increases.
G2 is a straight line with a negative slope. A decreasing function can still be linear.
G3 is an upward-opening parabola with one turning point. It is symmetric about x = -1.
G4 is a downward-opening parabola with one turning point. It is symmetric about x = 1.
G5 rises more steeply as x increases and approaches the x-axis on the left. Its outputs double for each increase of 1 in x.
G6 decreases and flattens toward the x-axis. Its outputs halve for each increase of 1 in x; it has no turning point.
The exponent t/6 counts the number of 6-hour doubling periods. At 18 hours, B(18) = 200 × 2³ = 1,600.
Each extra gigabyte adds the same $0.10. C(45) = 30 + 0.10 × 45 = 34.50.
Losing 15% leaves 85% of the preceding value each year. V(3) = 24,000 × 0.85³ = 14,739.
A adds a fixed amount each month; B multiplies the preceding balance by 1.04. Substitute n = 12 and n = 24 into both expressions. Retain full calculator precision until the final rounding.
At x = 3, the quadratic value 9 exceeds the exponential value 8. This counterexample rules out the claim that an exponential is always larger. For these two models, the exponential is larger at x = 5.
At x = 41, E ≈ 1,763.73, Q = 1,681 and L = 2,050; E has passed Q but is still below L. At x = 42, E ≈ 2,116.47, Q = 1,764 and L = 2,100, so E is above both. Checking the consecutive inputs 1 through 41 confirms that none meets both conditions.
In x², the variable is the base. In 2x, it is the exponent. A negative coefficient can flip a parabola without changing its family.
A narrow graph window can make a parabola and an exponential look similar. Look for a turning point, symmetry, or the output pattern.
A positive exponential with a base above 1 eventually exceeds linear and quadratic growth. It does not have to be largest at the input in the question.
For teachers and tutors: ask students to mark the input intervals before calculating differences. For graphs, have them point to the feature they used. Start with questions 1–18 and save the modeling questions for a second session if needed.
Berke Sahbazoglu is the founder of Burke Tutoring in Fremont. He teaches Algebra 1 and Algebra 2 and has more than 10 years of tutoring experience.
Found an error or a confusing question? Email Burke Tutoring with the question number and the part you would like clarified.
Originally published July 28, 2026. This revised worksheet has 24 questions; the online answers and PDFs use the same problem set.
For a longer explanation of the exponential family, see Paul’s Online Math Notes.
Print the questions first. Keep the answers handy for checking.